sum{k=1 to m} 1/k^n
Leroy Quet
qq-quet at mindspring.com
Fri May 28 16:52:40 CEST 2004
Consider the sequence where each term is a numerator of at least one
reduced rational
sum{k=1 to m} 1/k^n,
taken over all positive integers m and n.
So, unless I carelessly erred, the sequence begins:
1, 3, 5, 9, 11, 17, 25, 33, 49,...
(Not in EIS.)
3 things:
1) Except for 1 and 49, do any of the terms of this sequence correspond
with more than one {m,n}?
(49 is numerator when m = 6 and n = 1, and when m = 3 and n =2.)
2) We can consider also the sequence of denominators too, obviously.
3) Generally, we can apply the idea here to generating other sequences:
If we have any 2(or more)-index sequence {a(m,n)}, where the terms
consist of only a subset of all integers, then we can form the sequence
which contains the distinct integers (in numerical order) of {a(m,n)}.
thanks,
Leroy Quet
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