a Maple question

[Mohamud Mohammed]

Dear Emerich Deutsch,

if you rite a small procedure that

First factors and then use op opertation twice to out put in the required
format.

gu:=ifactor(n):
gu1:=[op(gu)]:
gu2:=[seq(op(1,gu1[i]),j=1..op(2,gu1[i]),i=1..nops(gu1)]:


mohamud m.
On Sat, 1 May 2004, Emeric Deutsch wrote:

> Dear Seqfans,
> I wonder whether this is an appropriate topic.
> Let me formulate my simple question on an example.
> The command ifactor(72) yields 2^3 3^2.
> I would like to get [2,2,2,3,3].
> Any idea? Thanks.
> Emeric
>
>