An application for zeroless squares
Paul C. Leopardi
leopardi at bigpond.net.au
Sat Apr 30 03:18:03 CEST 2005
Hi Matthjs,
I don't understand your puzzle. Maybe it is not completely specified below?
Thanks
On Fri, 29 Apr 2005 03:56 pm, Matthijs Coster wrote:
> Hello Seqfans,
>
> A month ago there was a discussion about zeroless squares.
> If you are interested read the (recreational) application below.
>
> Suppose you have to solve a crossword-puzzle of n x n.
> You have to fill it by the digits 0,...,9 and all the descriptions are
> equal, namely square of a number. How would you solve this
> crossword-puzzle, let's say crosssquare-puzzle?
>
> Important for solving this puzzle is to omit zeros at the first position.
Any number can be repesented using the digits 0 to 9. So are you asking for
any square number in any position of your n x n square, or are there any
other constraints?
> Well the 1 x 1 crosssquare-puzzle is easy. Only 1, 4, 9 are the solutions.
Why are 16, 25 etc. not solutions? Do you mean you only want single digit
squares? Then only 1, 4 or 9 can be in any position of the n x n square.
> If you are interested:
> number of solutions of the 2x2 puzzle is 4,
Are any of the five following 2 x 2 squares:
1 1
1 1
1 1
1 4
1 1
1 9
4 4
4 4
4 4
4 9
solutions?
Do you mean that you have no repetition? Then you would need to allow more
than 1, 4 and 9 in each position.
Are any of the six following 2 x 2 squares:
1 4
9 16
1 9
4 16
1 4
16 9
1 16
4 9
1 9
16 4
1 16
9 4
solutions?
Do you mean that each position in the n x n square is a digit of an n digit
number read across or downwards, and that each n digit number must be a
square?
Then are any of the six following 2 x 2 squares:
0 1
1 6
0 4
4 9
1 6
6 4
3 6
6 4
6 4
4 9
8 1
1 6
solutions? Are only the last four solutions because they do not contain
numbers with leading zeros? Is this why you say there are only four solutions
for 2 x 2?
Without further specification of the puzzle, I can't understand the rest of
your message.
Also, what happens in number bases other than ten, for example in binary?
> 3x3 : 13
> 4x4 : 14
> 5x5 : 76
> 6x6 : 40
> 7x7 : 459
>
> So therefore I introduce the sequence of number of solutions:
> 3, 4, 13, 14, 76, 40, 459, ...
>
> What will happen when n grows? I don't know. Important is the last position
> where only 0,1,4,5,6,9 can be placed. Therefore you have to find squares
> with only these digits. How do the number of squares behave?
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