Periodic Antisymmetric Matrices counted by Hermitte Numbers
Gottfried Helms
Annette.Warlich at t-online.de
Mon Dec 5 11:24:39 CET 2005
Am 03.12.2005 23:08 schrieb wouter meeussen:
> Antisymmetric: Transpose(A)= -A, so zero diagonals
> Periodic: some matrix power = Identity Matrix
> A067994= Hermitte Numbers= 1,0,2,0,12,0,120,0,1680, ...
>
> Their periods are all 4.
> Strong law of small numbers checked upto n=8.
> Who says this is self-evident?
>
> W.
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>
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A
0 2^0
2 2^1 *1
4 2^2 *1*3
6 2^3 *1*3*5
8 2^4 *1*3*5*7
10 2^5 *1*3*5*7*9 --- but this seems very regular.
What was your expectation about periods=4 ?
Is it something with phi()-function or order of cyclic subgroups?
Then the reason for some irregularity may be, that 9 isn't prime.
Gottfried Helms
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