(a*2^a)/(b*2^b)

Sam Handler shandler at macalester.edu
Sun Oct 9 06:03:19 CEST 2005


Hello,

I have discovered what I believe to be a new sequence:

1,3,4,5,6,8,9,10,11,12,14,16,17,18,20,24,32,33,34,36,37,40,42,48...

It is the set of natural numbers that can be expressed in the form

n = (a*2^a)/(b*2^b)

where a and b are natural numbers.

Can anyone check these numbers or extend the sequence? I am unsure that 
my method will find all possible results.

Any other ideas about this sequence would also be appreciated.

Thanks.

--Sam





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