(a*2^a)/(b*2^b)
Sam Handler
shandler at macalester.edu
Sun Oct 9 06:03:19 CEST 2005
Hello,
I have discovered what I believe to be a new sequence:
1,3,4,5,6,8,9,10,11,12,14,16,17,18,20,24,32,33,34,36,37,40,42,48...
It is the set of natural numbers that can be expressed in the form
n = (a*2^a)/(b*2^b)
where a and b are natural numbers.
Can anyone check these numbers or extend the sequence? I am unsure that
my method will find all possible results.
Any other ideas about this sequence would also be appreciated.
Thanks.
--Sam
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