(a*2^a)/(b*2^b)

[David Wilson]

1 3 4 5 6 8 9 10 11 12 14 16 17 18 20 24 32 33 34 36 37 40 42 48 52 64
65 66 67 68 70 72 76 80 88 96 112 128 129 130 132 135 136 142 144 156
160 184 192 240 256 257 258 260 264 272 288 320 352 384 448 512 513 514

The odd values seem to be of the form 2^n + odd divisor of n.

----- Original Message ----- 
From: "Sam Handler" <shandler at macalester.edu>
To: <seqfan at ext.jussieu.fr>
Sent: Sunday, October 09, 2005 12:03 AM
Subject: (a*2^a)/(b*2^b)


> Hello,
> 
> I have discovered what I believe to be a new sequence:
> 
> 1,3,4,5,6,8,9,10,11,12,14,16,17,18,20,24,32,33,34,36,37,40,42,48...
> 
> It is the set of natural numbers that can be expressed in the form
> 
> n = (a*2^a)/(b*2^b)
> 
> where a and b are natural numbers.
> 
> Can anyone check these numbers or extend the sequence? I am unsure that 
> my method will find all possible results.
> 
> Any other ideas about this sequence would also be appreciated.
> 
> Thanks.
> 
> --Sam