Comment to, and Lucas number analogue of, A08718

[Jonathan Post]

I just added a comment to A087018, based on an exercise in Thomas Koshy's
wonderful textbook on Fibonacci and Lucas numbers, which I shall duplicate
below.

Meanwhile, am I missing something, or does the OEIS not have the Lucas
number analogue of A087018:

a(n) = 1, 7, 38, 279, 3249, ...

row sums of Lucas number triangles as below:

1| 1.
2| 3, 4.
3| 7, 11, 18.
4| 29, 47, 76, 123.
5| 199, 322, 521, 843, 1364.

The solution in terms of L(n) = A000032(n) is related to the closed form
formula for A087018, as follows.

%I A087018
%S A087018 1, 3, 16, 123, 1453, 27060, 803383, 38256129, 2932126904,
%N A087018 Row sums of Fibonacci triangle shown below.
%C A087018 The first of the two new formulae I give here are equivalent
to the answer to Exercise 13, p.16, in the new Koshy reference cited.
%D A087018 T. Koshy, Fibonacci and Lucas Numbers with Applications,
Wiley-Interscience, 2001.
%F A087018 a(n) = F(T(n)+2) - F(T(n-1)+2) where T(n) = n-th triangular
number.
a(n) = A000045(A000217(n)+2) - A000045(A000217(n-1)+2).
%Y A087018 Cf. A000217.
%O A087018 1
%K A087018 ,easy,nonn,
%A A087018 Jonathan Vos Post (jvospost2 at yahoo.com
<http://us.f551.mail.yahoo.com/ym/Compose?To=jvospost2@yahoo.com&YY=80674&y5beta=yes&y5beta=yes&order=down&sort=date&pos=0&view=a&head=b>),
Dec 17 2006
RH
RA 192.20.225.32
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