New sequence : Primes for which SQRT(A000040(n)) < A001223(n)
Richard Guy
rkg at cpsc.ucalgary.ca
Tue Dec 12 19:16:18 CET 2006
Fools rush in ...
I believe that it would follow from the
Riemann hypothesis. R.
On Tue, 12 Dec 2006, Dean Hickerson wrote:
> Mostly to David Wilson:
>
> Concerning primes p for which there are no primes between p and p+sqrt(p),
> you asked:
>
>> Wouldn't the finiteness of this sequence follow from the prime number
>> theorem?
>
> Not that I can see. Do you have a proof?
>
> Note that finiteness of this sequence implies that, for every sufficiently
> large positive integer n, there's a prime between n^2 and (n+1)^2. Except
> for the "sufficiently large", that's Legendre's conjecture, which is still
> unproved.
>
> Dean Hickerson
> dean at math.ucdavis.edu
>
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