Need help with sequences
Zakir Seidov
zakseidov at gmail.com
Thu Dec 28 05:56:24 CET 2006
If we reduce slightly the requirement and
look for numbers n such that n|tanya4(n), then we have
{tanya4(n)/n,n}}:
{{4, 1}, {8, 2}, {64, 4}, {8192, 8}, {964, 17}, {9040, 29},
{20, 52}, {68,64}, {1024, 68}, {7, 624}, {384, 694},
{112,768}, {284, 924}, {14, 1172}, {20, 3281},
{1, 4624}, {2, 6656}, {8, 8234}, {28, 9664},
{4, 98384}, {1, 595968}},..
Next term(s)?
Some SeqFan with C++ may wish to go further,
Zak
tanya4[n_]:=(Plus @@ (4^IntegerDigits[n]))
--- Tanya Khovanova <tanyakh at TanyaKhovanova.com> wrote:
<.....>
> Number 1:
> 4624, 595968 - Numbers n such that the sum of the 4
> to the powers of its digits equals n.
<..............>
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