Need help with sequences

Max A. maxale at gmail.com
Wed Dec 27 22:51:26 CET 2006


CORRECTION:

This is a finite sequence, and you have found all its terms.

Indeed, if the number consists of n decimal digits then
1) the sum of the 4 to the powers of its digits is at most n*4^9;
2) the number itself is at least 10^(n-1).
But it is easy to see that 10^(n-1) > n*4^9 for n>=8. Therefore, all
numbers in this sequence have at most 7 decimal digits.

Max

On 12/27/06, Max A. <maxale at gmail.com> wrote:
> On 12/27/06, Tanya Khovanova <tanyakh at tanyakhovanova.com> wrote:
>
> > Number 1:
> > 4624, 595968 - Numbers n such that the sum of the 4 to the powers of its digits equals n.
> > Comment: If you use 2 instead of 4, such numbers do not exist. If you use 3, the only number is 12.
> > Example: 4^4 + 4^6 + 4^2 + 4^4 = 256 + 4096 + 16 + 256 = 4624.
> > Math: Select[Range[10000000], Plus @@ (4^IntegerDigits[#]) == # &]
>
> This is a finite sequence, and you have found all its terms.
>
> Indeed, if the number consists of n decimal digits then
> 1) the sum of the 4th powers of its digits is at most n*9^4;
> 2) the number itself is at least 10^(n-1).
> But it is easy to see that 10^(n-1) > n*9^4 for n>=6. Therefore, all
> numbers in this sequence have at most 5 decimal digits.
>
> Max
>






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