A084057-A110940, and a bunch of duplicates.
Lambert Herrgesell
zero815 at googlemail.com
Sun Jan 8 21:57:49 CET 2006
Dear seqfans,
There are several sequences with a similar name, for example
A110940 Starting a priori with the fraction 1/1, the numerators of fractions
built according to the rule: add top and bottom to get the new
bottom,
add top and 5 times the bottom to get the new top.
most of them are duplicates.
instead of reading a(n) as the numerator of a fraction 1/1, read it as
separeate
sequence elements 1,1, i.e. a(n-2), a(n-1),
then (with a sign switch of a permutation), a(n) = a(n-1)+5a(n-2) +(a(n-1)
- a(n-2)) = 2a(n-1)+4a(n-2)
(for both the top and the bottom part)
To make the dubious more obvious, the conversion by example:
a(1)=1,a(2)=1;
a(3) = a(2) + 5a(1)
b(3) = a(2) + a(1)
a(4) = a(3) + 5b(3) // substitute b(3) by a(2) + a(1)
= a(3) + 5(a(2) + a(1))
= a(3) + 5a(2) + 5a(1) // extract another a(3)
= 2a(3) + 4a(2)
and so on and so on ...
so a(n) = 2a(n-1) + 4a(n-2) which is A084057.
A similar argument also makes
A015519 - A110948
A001333 - A110934
A046717 - A110938
A015518 - A110939
A002533 - A110942
A002532 - A110943
A084058 - A110946 (A083100)
duplicates.
best
Lambert
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