Kimberlike sequence (for k=10)

[Eric Angelini]

I wrote:

> Looks like, yes, it is always possible to fill the "holes"...

... mmmmh, not so sure now; Gilles Sadowski computed 5000 terms
for k=10 and integers 2, 4, 6, 8, 9, ... are still missing!
... this pb is like packing combs of k=2, 3, 4... teeth in the most
economical way... Wish I was bald...
Best,
É.
(see bottom of page for k=10):
http://www.cetteadressecomportecinquantesignes.com/Kimberlike02.htm