Conjugate m-dimensional partitions
Max
maxale at gmail.com
Sat May 13 21:05:03 CEST 2006
On 5/13/06, franktaw at netscape.net <franktaw at netscape.net> wrote:
> I have submitted that table as pre-numbered sequence A119269. It looks
> like you have a few more values; please extend it once it's out there
> (which should be soon).
OK.
> Your three "guessed" values are correct, assuming the accuracy of your
> other numbers. The final increments in the columns become fixed (as
> you conjecture) once you get to twice the dimension;
Do you have a proof for that?
> in reverse order,
> 1, 2, 6, 19, and (from your numbers) 60. This could be A052544, but I
> have no particular reason to think it is.
It may be also interesting to consider partial sums of that sequence which is
s(k): 0, 0, 1, 3, 9, 28, 88 (for k=1..7)
so that for any fixed k and large enough m,
T(m,m+k) = a(m+k) - s(k)
where a(n) = T(n-2,n) is the number of infinity-dimensional partitions
of n up to conjugacy.
Max
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