A050259 and a new solution to 2^n = 3 (mod n)

[Max A.]

SeqFans,

In course of exploring all solutions of the congruence 2^n = 3 (mod n)
below 10^16, I have found a new solution:

n = 3468371109448915

This came as a big surprise to me since my original goal was to prove
that 8365386194032363 is the second term of A050259. But now it
appears to be at least the third term.

So far I've submitted the new solution as a comment to A050259, but
hopefully it will take its true place in this sequence soon.

Regards,
Max

P.S. See also http://mathworld.wolfram.com/2.html