A050259 and a new solution to 2^n = 3 (mod n)

[Richard Guy]

Congratulations!  May I know Max's full name,
so that he can earn undying fame in UPINT as
well as in OEIS ?   Thanks,   R.

On Mon, 13 Nov 2006, Max A. wrote:

> SeqFans,
>
> In course of exploring all solutions of the congruence 2^n = 3 
> (mod n)
> below 10^16, I have found a new solution:
>
> n = 3468371109448915
>
> This came as a big surprise to me since my original goal was 
> to prove
> that 8365386194032363 is the second term of A050259. But now 
> it
> appears to be at least the third term.
>
> So far I've submitted the new solution as a comment to 
> A050259, but
> hopefully it will take its true place in this sequence soon.
>
> Regards,
> Max
>
> P.S. See also http://mathworld.wolfram.com/2.html