A065577 Number of Goldbach partitions of 10^n? More terms?

[zak seidov]

David, Dick, Bob, Ivars,
seqfans.

After recalculating (at two different PC's)
and rechecking I could finally 
find source of my error
(silly as usual) in one of codes,
and my final value is 
a(10) = 18200488 (NOT 18200487!)
which coincides now with the Dick-David value.

So, Bob, 
you may wish to give in A065577  the correct value 
a(10) = 18200488 with due refer to David Wilson  and
Richard Mathar (not me).
Also Ivars can extend his table.
Thanks, Zak

BTW1 Still, is it possible to find a(11)... with C++?

BIW2 Not all people even in this closed list
may be interested in Mmca specific problems,
so I''l be happy to have a list of you
particularly Mmca-involved.
Then we may circulate relevant messages
not to all seqfan community.
Please anyone interested write me personally
with subject "Me in Mmca", thanks.
Of course it's not intented to be closed list!
Hope this is not against Gerard' policy.

--- David Wilson <davidwwilson at comcast.net> wrote:

> Regarding A065577:
> 
> I altered my counting program to generating a file
> listing, in increasing 
> order, all primes p such that there exists prime q
> with p < q, p+q = 10^10. 
> I wrote a verification program to read this file,
> check that the p are in 
> increasing order, count the p, compute q = 10^10-p,
> check p < q and that p 
> and q are both prime (using trial division).
> 
> The verification program has finished, and confirms
> that a(10) >= 18200488. 
> This contradicts Zak Seidov's count a(10) =
> 18200487, but agrees with Dick 
> Mathar's count a(10) = 18200488.
> 
> If anyone is interested, I am keeping the text file
> with the p values for a 
> little while. It is 195MB, so e-mailing it is
> probably not a good option.
> 
> 



 
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