A121923 = A051177 ?

[Joseph Biberstine]

Absolutely; the %N lines are equivalent.

zak seidov wrote:
> A121923  = A051177?
> 
> %I A051177
> %S A051177
> 1,2,3,124,158,342,693,1896,3853,4434,5273,8640,14850,17928,110516,
> %T A051177 178984,274534
> %N A051177 Perfectly partitioned numbers: n divides
> the number of partitions p(n) of n.
> %D A051177 Journal of Recreational Mathematics, vol.
> 29, #4, pg 304, problem 2464.
> %D A051177 Journal of Recreational Mathematics, vol.
> 30(4) 294-5 1999-2000, Soln. to prob.2464, 
>                "Perfect Partitions".
> %e A051177 a(4) = 124 because p(124) = 2841940500 is
> divisible by 124.
> %Y A051177 Cf. A000041.
> %Y A051177 Sequence in context: A041813 A065842
> A065841 this_sequence A095841 A004865 A006286
> %Y A051177 Adjacent sequences: A051174 A051175 A051176
> this_sequence A051178 A051179 A051180
> %K A051177 hard,nice,nonn
> %O A051177 1,2
> %A A051177 M.A. Muller (MAM(AT)LAND.SUN.AC.ZA)
> %E A051177 Are there infinitely many perfectly
> partitioned numbers? Does there exist some n 
>                for which p(n) is a perfectly
> partitioned number?
> %E A051177 More terms from Don Reble (djr(AT)nk.ca),
> Jul 26 2002
> 
> %I A121923
> %S A121923
> 1,2,3,124,158,342,693,1896,3853,4434,5273,8640,14850,17928
> %N A121923 Numbers n such that (partition number of n)
> == 0 modulo n.
> %C A121923 Or n divides partition number of n. Cf.
> A093952 Partition number A000041(n) mod 
>                n.
> %e A121923 a(7) = 693 because partition number of 693
> is
> %e A121923 43397921522754943172592795 =
> 693*62623263380598763596815;
> %o A121923 (PARI)
> for(n=1,20000,if(numbpart(n)%n==0,print1(n,",")))  -
> (Klaus Brockhaus, Sep 
>                06 2006)
> %Y A121923 Cf. A000041, A093952.
> %K A121923 more,nonn,new
> %O A121923 1,2
> %A A121923 Zak Seidov (zakseidov(AT)yahoo.com), Sep 02
> 2006
> %E A121923 a(8) to a(14) from Klaus Brockhaus
> (klaus-brockhaus(AT)t-online.de), Sep 06 2006
> 
> 
> 
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