A121923 = A051177 ?

[zak seidov]

Hence A121923 must be dead (?!)
(...unfortunately to Zak...)

Thanks, Zak

--- Joseph Biberstine <jrbibers at indiana.edu> wrote:

> Absolutely; the %N lines are equivalent.
> 
> zak seidov wrote:
> > A121923  = A051177?
> > 
> > %I A051177
> > %S A051177
> >
>
1,2,3,124,158,342,693,1896,3853,4434,5273,8640,14850,17928,110516,
> > %T A051177 178984,274534
> > %N A051177 Perfectly partitioned numbers: n
> divides
> > the number of partitions p(n) of n.
> > %D A051177 Journal of Recreational Mathematics,
> vol.
> > 29, #4, pg 304, problem 2464.
> > %D A051177 Journal of Recreational Mathematics,
> vol.
> > 30(4) 294-5 1999-2000, Soln. to prob.2464, 
> >                "Perfect Partitions".
> > %e A051177 a(4) = 124 because p(124) = 2841940500
> is
> > divisible by 124.
> > %Y A051177 Cf. A000041.
> > %Y A051177 Sequence in context: A041813 A065842
> > A065841 this_sequence A095841 A004865 A006286
> > %Y A051177 Adjacent sequences: A051174 A051175
> A051176
> > this_sequence A051178 A051179 A051180
> > %K A051177 hard,nice,nonn
> > %O A051177 1,2
> > %A A051177 M.A. Muller (MAM(AT)LAND.SUN.AC.ZA)
> > %E A051177 Are there infinitely many perfectly
> > partitioned numbers? Does there exist some n 
> >                for which p(n) is a perfectly
> > partitioned number?
> > %E A051177 More terms from Don Reble
> (djr(AT)nk.ca),
> > Jul 26 2002
> > 
> > %I A121923
> > %S A121923
> >
>
1,2,3,124,158,342,693,1896,3853,4434,5273,8640,14850,17928
> > %N A121923 Numbers n such that (partition number
> of n)
> > == 0 modulo n.
> > %C A121923 Or n divides partition number of n. Cf.
> > A093952 Partition number A000041(n) mod 
> >                n.
> > %e A121923 a(7) = 693 because partition number of
> 693
> > is
> > %e A121923 43397921522754943172592795 =
> > 693*62623263380598763596815;
> > %o A121923 (PARI)
> > for(n=1,20000,if(numbpart(n)%n==0,print1(n,","))) 
> -
> > (Klaus Brockhaus, Sep 
> >                06 2006)
> > %Y A121923 Cf. A000041, A093952.
> > %K A121923 more,nonn,new
> > %O A121923 1,2
> > %A A121923 Zak Seidov (zakseidov(AT)yahoo.com),
> Sep 02
> > 2006
> > %E A121923 a(8) to a(14) from Klaus Brockhaus
> > (klaus-brockhaus(AT)t-online.de), Sep 06 2006
> > 
> > 
> > 
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