request for help in clarifying definition of sequence

[T. D. Noe]

At 10:24 AM -0400 9/16/06, N. J. A. Sloane wrote:
>Dear Seqfans,
>
>At present there is this entry:
>
>%I A120401
>%S A120401
>0,1,2,3,4,5,6,7,8,9,10,11,12,13,15,16,17,18,19,20,22,23,24,26,27,28,29,
>%T A120401
>31,33,34,35,36,38,39,41,42,44,45,46,47,50,51,53,54,55,57,58,61,62,63,
>%U A120401 64,66,68
>%N A120401 Consider the zeros of the Riemann zeta function. Sequence gives
>the decimal part values which are nonzero.
>%D A120401 http://www.dtc.umn.edu/~odlyzko/zeta_tables/zeros1
>%e A120401 The first zero is 14.13472.. so 0,1,2,3,4,5,6,7,8,9,10,11,12,13
>are part of the sequence
>%e A120401 The second zero is 21.02203.. so 15,16,17,18,19,20 are in the
>sequence too
>%e A120401 The third zero is 25.0108.. so 22,23,24, etc.
>%K A120401 fini,nonn,uned,obsc
>%O A120401 0,3
>%A A120401 Jorge Coveiro (jorgecoveiro(AT)yahoo.com), Jul 02 2006
>
>I asked the author for more information.
>
>Dear Jorge,
>could you give a better definition of this sequence?
>I find it very confusing.
>
>and you might explain how it related to A002410!
>
>best
>
>Neil
>
>----
>
>
>He said:
>
>ok  A002410  it the nearest integer to the imaginary part.
>
>  but imagine that there is a sequence that the integer part
>  is the integer part of the imaginary part of zeta. (not the nearet one)
>  I mean like (ceil function).
>
>  now A120401 is suppose to be the inverse of that function
>  so the numbers are fini. because when zero imaginary parts
>  become bigger they become all integer. so there must exist
>  a minimum number of integer numbers that are not associated
>  with any zero....  maybe I can finish the sequence by myself,
>  but I think it's big...  maybe a few hundred numbers. but it's fini.
>  because the zeta zeros become close
>
>
>
>---
>
>I am still confused.  Could someone help and edit this sequence?

I vote for making it the complement of A002410.  I looked at the first 10^5
zeta zeros and found 4562 terms of this sequence (if it is the complement
of A002410).  Seems to be finite, but large.

Tony