Please Help Me!!!

Max Alekseyev maxale at gmail.com
Tue Dec 11 02:34:54 CET 2007


It looks like Lekraj has got some kind of trojan program that sends
out scam emails to everybody in his address book.
Lekraj, if you read this email, please clean up your system with
modern anti-virus and anti-spyware tools.

Regards,
Max

On Dec 10, 2007 5:15 PM, Lekraj Beedassy <boodhiman at yahoo.com> wrote:
>
> How are you doing today? I am in a hurry writing you this message, as i
> don't have much time on the pc here, However i have a brief message to pass
> over to you about my
> present situation which requires your urgent response. Actually, I had a
> trip to Nigeria few days ago for a program called "Empowering Youth to Fight
> Racism, HIV/AIDS, Poverty and Lack of Education, the program is taking place
> in three major countries in Africa which is Ghana, South Africa and Nigeria.
> but unfortunately for me all my money got stolen at the hotel where i lodged
> due to a robbery incident that happened in the hotel. I had been so restless
> since last night, i have been without any money i am even owing the hotel
> here as well, moreover the Hotel's telephone lines here got disconnected by
> the robbers and they are trying to get them fixed back.
> I have access to only emails at the library because my cell cant work here
> so i didn't bring it along, please i want you to help me with some money so
> that i can clear my bills and return back home. I am in a terrible situation
> right now because am with no money. I want you to help me with some amount
> of money as I am now owning a hotel bill of $800 and they want me to pay up
> my Hotel bills soon else they will hand me over to the Hotel Management, And
> i will also need $1100 to fly back to the states. If you can you help me
> with a sum of $2000 to sort out my problems here. I would be very greatful,
> I need this money so bad that I can't even endure, I don't even have any
> money to call overseas nor shelter myself for a day which means I have been
> starving so bad. so please understand how urgent it is. so i can return back
> i would refund it back to you as soon as i get home, I am so confused right
> now and don't know what to do, you can have it sent through Western Union
> but My passport is with the Embassy here so not sure if i can use my name to
> collect it now, But you can send it directly to a Man who works for Western
> Union, he helps people in the hotel i lodge to get money from their
> relatives and i would get it through him, I have already spoke to him, so he
> will get it immediately it is sent but let me know if you can help me then i
> will make findings. Its really urgent for me as i don't know what to do
> right now than to leave here as soon you have the money sent.i will refund
> back the money immediately i get back home.
> and do me a favor, Don't tell anyone about my condition. Below is the guy's
> information that works for Western Union over here.
> Name: Nad Betty
> Address: 1 Air port Hotel.
> City: Ikeja
> State: Lagos
> Zip code: 23401
> Country: Nigeria
> Text Question: What is the money for?
> Answer: Hotel Bills
>                        As soon as you send the money, please email me with
> the Money Transfer Control Number(10 Digits MTCN ), full sender's name, text
> question and answer and
> amount sent, I will appreciate your help at this time and I promise to pay
> back whenever I return back to state.
> Lekraj.
>
>
>  ________________________________
> Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it
> now.



%I A000001 
%S A000001 1,1,5,43,875,49506
%N A000001 The number of multisets A={a_1,a_2,...a_n} such that prod{1+1/a_i}=2
%e A000001 The multiset A={3,3,8} has prod{1+1/a_i}=4/3*4/3*9/8=2; a(3)=5 because there are 5 such sets with 3 elements (the others being {2,4,15}, {2,5,9}, {2,6,7}, {3,4,5})
%C A000001 For given n, the largest element appears in the set {2, 4, 16, 256, ... 2^2^(n-2), 2^2^(n-1)-1}
%C A000001 If k is in A, then there are tau(k(k+1))/2 possible n+1-element sets {A-k \union {k+x, k+y}} that also have the property, where xy=k(k+1)
%K A000001 nonn,more,new
%O A000001 1,3
%Y A000001 Cf. A002966, the parallel sequence for sum{1/a_i}=1
%A A000001 Hugo van der Sanden (hv at crypt.org)

I'd welcome confirmation of the last term, and more terms: I don't have
time to do more with this right now.

Inspired by an aside in A066218, this actually originated as: find n such
that 2 tau(n) = sum_{d | n} tau(d); these multisets are the powers+1 in
the prime factorisation of any such n.

This seems like quite an interesting set to investigate further: it is not
at in the second comment (parallel to (tau(k^2)+1)/2 in the sum case).

The sets contributing to a(1)..a(4) are:

<1> ; <2 3> ; <2 4 15> <2 5 9> <2 6 7> <3 3 8> <3 4 5> ;
<2 4 16 255> <2 4 17 135> <2 4 18 95> <2 4 19 75> <2 4 20 63> <2 4 21 55>
<2 4 23 45> <2 4 25 39> <2 4 27 35> <2 4 30 31> <2 5 10 99> <2 5 11 54>
<2 5 12 39> <2 5 14 27> <2 5 15 24> <2 5 18 19> <2 6 8 63> <2 6 9 35>
<2 6 11 21> <2 6 14 15> <2 7 7 48> <2 7 8 27> <2 7 9 20> <2 7 12 13>
<2 8 9 15> <2 9 10 11> <3 3 9 80> <3 3 10 44> <3 3 11 32> <3 3 12 26>
<3 3 14 20> <3 3 16 17> <3 4 6 35> <3 4 7 20> <3 4 8 15> <3 4 10 11>
<3 5 5 24> <3 5 6 14> <3 5 8 9> <3 6 7 8> <4 4 5 15> <4 5 5 9> <4 5 6 7>

.. and I'd include them in a sequence of their own if I could think of
a useful way to arrange it. (The original 2tau(n) interpretation may
also be worth submitting.)

Hugo





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