Minimal graphs for groups
franktaw at netscape.net
franktaw at netscape.net
Tue Jan 9 22:44:11 CET 2007
A080803 (the size of the smallest graph whose symmetry group has n
elements) and A058890 (the size of the smallest graph whose symmetry
group is cyclic of order n) are closely related. It seems to me that
they should have cross-references to each other:
%Y A080803 Cf. A058890.
%Y A058890 Cf. A080803.
They should also have the same value for a(1), since the cyclic group
is the only group of order 1. In particular, I think A058890(1) should
be 0.
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It also occurs to me to wonder about the equivalents of these sequences
for digraphs. One can always get a digraph on n nodes whose symmetry
group is C_n by just connecting them in a cycle. I think this means
that the digraph equivalent of A058890 is actually A008457 (sum of
unitary prime power divisors).
For the equivalent of A080803, A001414 is an upper bound. Given a set
of digraphs D_i whose symmetry groups have order k_i, one can construct
a digraph on the union whose order is Product k_i. Since the
complement of a disconnected graph is connected, and the complement of
a graph (or digraph) has the same symmetry group, we can take all the
D_i to be connected. Now if there are two isomorphic components,
combine them into one by adding an arrow from each point in one to each
point in the other; repeat as necessary. Once all components are
distinct, the symmetry group of the disjoint union will be the direct
product of the symmetry groups of the D_i's.
A001414 is not exact, however; in particular, a(6) = 3, while
A001414(6) = 5.
I think we start:
0,2,3,4,5,3,7,4,6,7,11,7,13,9,8,6,17,6,19,9,10,13,23,4
Franklin T. Adams-Watters
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