a remarkable coincidence showing that numerical data can be misleading!

[Robert Gerbicz]

2007/6/7, Jonathan Post <jvospost3 at gmail.com>:
>
> Should there be something equivalent for a(n) = 3/(3^(1/n)-1 with n =
> 1, 2, 3, ...
>
> 2, 5, 7, 10, 13, 15, 18, 21, 24, 26, 29, 32, 35, 37, 40, ...?
>
> or, corrected parenthesization:
>
> 3/(3^((1/15)-1)) for n = 1, 2, 3, ...
>
> 3, 6, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9,
> convergent to 9.
>
> It's not an exact analogue, as b(n) = floor((3*n/(log 3))) begins with
> n = 0, 1, 2, 3, ...:
>
> 0, 6, 12, 18, 25, 31, 37, 44, 50, 56, 62, 81, 88, 94, ...
>
> and I don't see an obvious correlation between a(n) and b(n).


In general the question is the following:  if k is a given positive integer,
k>1 We are searching for n values for that ceil(2/(k^(1/n)-1) isn't equal to
floor(2*n/log(k))


Max: I've checked, your b file is good.
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