trouble submitting new sequences or comments today?

[N. J. A. Sloane]

sequence to test the web page, and so far it has not arrived.
 U882 kolotoko at wanadoo.fr   Sat Nov 24 15:49  57/3160  SEQ FROM Philippe DELEHAM
 U595 martin_n_fuller at btin  Sat Nov 24 18:12  41/2563  COMMENT Martin Fuller A132363
 N  2 grafix at csl.pl         Sat Nov 24 17:32  56/2715  SEQ+# A135251 FROM Artur Jasinski
 N  3 pauldhanna at juno.com   Sat Nov 24 18:01  62/2863  SEQ+# A135079 FROM Paul D. Hanna
 N  4 grafix at csl.pl         Sat Nov 24 18:40  65/3994  SEQ+# A135252 FROM Artur Jasinski
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Message-ID: <5542af940711241931g7f81f91dy2db02095ce78423e at mail.gmail.com>
Date: Sat, 24 Nov 2007 19:31:59 -0800
From: "Jonathan Post" <jvospost3 at gmail.com>
To: "Sequence Fans" <seqfan at ext.jussieu.fr>,
   "jonathan post" <jvospost2 at yahoo.com>, "Omar E. Pol" <info at polprimos.com>
Subject: Towards a comment on A134941 Mountain numbers
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I'd be interested to see the following elementary seq expanded, and so
might Omar E. Pol:

Number of mountain numbers with n digits.

n  a(n)
1  1
2  0
3  8
4  56 (7 each beginning 12, 13, 14, 15, 16, 17, 18, 19)
5  <5488
           2744 =(56 ascending substrings * 49 descending substrings)
          + 2744 (49 ascending substrings * 56 descending substrings)
          - those which were double-counted in the above

Partial sums of this will give, ultimately, the total number of
mountain numbers of any length of which 12345678987654321 is the
largest.

Is it mere coincidence that the first 4 values coincide with A093134 A
Jacobsthal trisection?

All this, of course, is base 10.  What are the sequences and counts
with other bases?

Best,

Jonathan Vos Post