d(m) = d(m+1) = 2n

[Leroy Quet]

Consider the two sequences, one of positive integers m and one of positive integers n:
m and n are such that m is the smallest positive integer with 2n divisors, and m+1 also has 2n divisors.

For example, 2 has 2 divisors, and 2+1 also has 2 divisors. And 2 is the smallest positive integer with 2 divisors.

So the m sequence starts: 2,...
And the n sequence starts: 1,...

This may be easily answered, I bet, but are there any other m's and n's?

Thanks,
Leroy Quet