[seqfan] amicable numbers - Conjecture

[vincenzo.librandi at tin.it]

 Let p = prime number

if 2^n=[2*(p+1)/3]

b=2*p+1 (with b=prime)

c=2*p^2+4*p+1 (with c=prime)

then

p*b*2^n   and   c*2^n

are amicable numbers

Best Regards

Vincenzo Librandi