[seqfan] Re: Sum divides concatenation
Jack Brennen
jfb at brennen.net
Thu Oct 1 00:02:09 CEST 2009
As I posted already, it's 1913932644.
Robert G. Wilson, v wrote:
> ALCON,
>
> The next term is over 1.1 billion.
>
> Bob.
>
> ----- Original Message -----
> From: "Charles Greathouse" <charles.greathouse at case.edu>
> To: "Sequence Fanatics Discussion list" <seqfan at list.seqfan.eu>
> Sent: Monday, September 28, 2009 1:23 PM
> Subject: [seqfan] Re: Sum divides concatenation
>
>
> It's not in the database. The terms are
> 1, 2, 6, 250488, 19986, 118030, 133970, 693810, 2231328, 3407286,
> 5733260, 25176334, 75529002, ...
>
> The next term is more than 100 million. A good program could find
> these values quickly, but I just used a few minutes of brute force.
>
> Charles Greathouse
> Analyst/Programmer
> Case Western Reserve University
>
> On Mon, Sep 28, 2009 at 12:35 PM, Jack Brennen <jfb at brennen.net> wrote:
>> The next term would be 250488, if that's any help:
>>
>> 126250488 == (1+2+6+250488) * 504
>>
>> Eric Angelini wrote:
>>> Hello SeqFans,
>>> I don't know how to find more terms -- thus I don't know
>>> if this is old hat in Neil's database:
>>>
>>> 1, 2, 6, ...
>>>
>>> The sum of the first n integers divides the concatanion of
>>> the first n integers; always prolong the seq with the smal-
>>> lest _natural_ number not yet used:
>>>
>>> 1 divides 1 --> HIT
>>> 1+2 (=3) divides 12 --> HIT
>>> 1+2+3 (=6) does not divide 123
>>> 1+2+4 (=7) does not divide 124
>>> 1+2+5 (=8) does not divide 125
>>> 1+2+6 (=9) divides 126 --> HIT
>>> etc.
>>>
>>> Best,
>>> É.
>>>
>>>
>>> _______________________________________________
>>>
>>> Seqfan Mailing list - http://list.seqfan.eu/
>>>
>>>
>>
>>
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