[seqfan] Re: a simple Partitions question
N. J. A. Sloane
njas at research.att.com
Sun Mar 21 16:41:09 CET 2010
Wouter, I'll add this to the OEIS:
%I A078198
%S A078198 1,2,4,6,11,13,18,20,22,23,26,29,31,38,45,47,50,53,72,75,78,80,87,
%T A078198 94,99,103,107,112
%N A078198 Numbers that cannot be partitioned into positive powers of 3, 5 and 7.
%e A078198 2271 is a memeber because 2271 = 3^1 + 3^2 + 3^3 + 3^4 + 3^5 + 3^6 + 5^1 + 5^2 + 5^3 + 5^4 + 7^1 + 7^2 + 7^3.
%O A078198 1,2
%K A078198 nonn,more
%A A078198 Wouter Meeussen, Mar 20 2010
What about the sequence giving the num ber of such representations?
How does it begin?
Neil
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