[seqfan] Re: a simple Partitions question
Richard Mathar
mathar at strw.leidenuniv.nl
Sun Mar 21 18:04:20 CET 2010
> %I A078198
> %S A078198 1,2,4,6,11,13,18,20,22,23,26,29,31,38,45,47,50,53,72,75,78,80,87,
> %T A078198 94,99,103,107,112
> %N A078198 Numbers that cannot be partitioned into positive powers of 3, 5 and 7.
> %e A078198 2271 is a memeber because 2271 = 3^1 + 3^2 + 3^3 + 3^4 + 3^5 + 3^6 + 5^1 + 5^2 + 5^3 + 5^4 + 7^1 + 7^2 + 7^3.
> %O A078198 1,2
> %K A078198 nonn,more
> %A A078198 Wouter Meeussen, Mar 20 2010
Better: numbers that cannot be partitioned into DISTINCT strictly positive
powers of 3, 5 and 7, because 6=3^1+3^1, 11=3^1+3^1+5^1 etc are
representations with repeated positive powers which are apparently
not counted/admitted.
And: 3^0=1 is a positive power (albeit the exponent isn't), so what is
actually meant (?) is
Numbers that cannot be partitioned into distinct powers of 3, 5 and 7, each part >1.
The example needs negation: 2271 is NOT a member because .. is such a partition.
The auxiliary complementary sequence to A078198 is
"Numbers that can be partitioned.." = 3,5,7,8,9,10,12,14,15,16,17,...
And on that one could define "Numbers of partitions of A.....(n) into forms..."
3 -> 1 (namely 3)
5 -> 1 (namely 5)
7 -> 1 (namely 7)
8 -> 1 (namely 3+5)
9 -> 1 (namely 3^2)
10 -> 1 (namely 3+7)
12 -> 2 (namely 5+7, 3+3^2)
14 -> 1 (namely 5+3^2)
15 -> 1 (namely 3+5+7)
16 -> 1 (namely 7+3^2)
17 -> 1 (namely 3+5+3^2
19 -> 1 (namely 3+7+3^2)
21 -> 1 (namely 5+7+3^2)
24 -> 1 (namely 3+5+7+3^2)
25 -> 1 (namely 5^2)
27 -> 1 (namely 3^3)
28 -> 1 (namely 3+5^2)
30 -> 2 (namely 5+5^2 = 3+3^3)
32 -> 2 (namely 7+5^2 = 5+3^3)
33 -> 1 (namely 3+5+5^2)
34 -> 2 (namely 3^2+5^2 = 7+3^3)
to yield a sequence (everybody please check)
1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 2, 2, 1,
3, 3, 1, 2, 2, 1, 2,
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