[seqfan] Re: n < 2^tau(n)

[zak seidov]

--- On Sun, 5/30/10, Leroy Quet <q1qq2qqq3qqqq at yahoo.com> wrote:

> %C A175495 After the initial 1 in this sequence, the first integer in this sequence but not in A034884 is 44. 

Me: All terms of A034884 are also in A175495.
Zak

--- On Sun, 5/30/10, Leroy Quet <q1qq2qqq3qqqq at yahoo.com> wrote:

> From: Leroy Quet <q1qq2qqq3qqqq at yahoo.com>
> Subject: [seqfan]  n < 2^tau(n)
> To: seqfan at seqfan.eu
> Date: Sunday, May 30, 2010, 8:38 AM
> I just submitted this sequence.
> 
> %S A175495
> 1,2,3,4,6,8,10,12,14,15,16,18,20,24,28,30,32,36,40,42,44
> %N A175495 Those positive integers n where n < 2^d(n),
> where d(n) = number of divisors of n. 
> %C A175495 After the initial 1 in this sequence, the first
> integer in this sequence but not in A034884 is 44. 
> %C A175495 This sequence is those n where A175494(n) = 1. 
> %Y A175495 CF. A175494, A034884 
> %K A175495 more,nonn
> %O A175495 1,2
> 
> (By the way, A175494(n) = floor(n^(1/d(n))).)
> 
> 
> Is this sequence (A175495) finite?
> 
> Thanks,
> Leroy Quet
> 
> [ ( [ ([( [ ( ([[o0Oo0Ooo0Oo(0)oO0ooO0oO0o]]) ) ] )]) ] )
> ]
> 
> 
>       
> 
> 
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