[seqfan] Re: A169828: more terms? in pairs (6k,6k+1)?

Max Alekseyev maxale at gmail.com
Mon May 31 21:34:27 CEST 2010

On Mon, May 31, 2010 at 2:35 PM, zak seidov <zakseidov at yahoo.com> wrote:

> 2. Is suggestion that entries appears in pairs
>  (6k,6k+1) OK? At least first six entries are.

That's a trivial observation.
If m is an even term of A169828, then it is also divisible by 3, i.e.,
m=6k, and m+1 is also a term of A169828.
On the other hand, if m is an odd term of A169828, then m == 1 (mod 3)
and thus m=6+1, implying that m-1 is also a term of A169828.


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