[seqfan] Re: Occupancy count maps perfect squares
Ron Hardin
rhhardin at att.net
Mon Dec 17 09:19:51 CET 2012
It's not symmetric because there's no vertical movement.
rhhardin at mindspring.com
rhhardin at att.net (either)
----- Original Message ----
> From: Giovanni Resta <g.resta at iit.cnr.it>
> To: seqfan at list.seqfan.eu
> Sent: Mon, December 17, 2012 2:50:47 AM
> Subject: [seqfan] Re: Occupancy count maps perfect squares
>
> On 12/16/2012 07:43 PM, Ron Hardin wrote:
> > The top corner of this problem seems to have even columns equal to perfect
> > squares, as far as it's been computed.
> >
> > Can it be seen why this might be?
> >
> > T(n,k)=Number of nXk arrays of occupancy after each element moves to some
> > horizontal, diagonal or antidiagonal neighbor
>
> Honestly, I do not understand what do you mean with that definition.
> At a certain point I thought you mean
> "start with a matrix n x k filled with ones and count
> how many configuration can be obtained if every one can be
> moved (added) to a neighbouring cell.
>
> Hover, if that was the case, I would expect a symmetric table of result,
> so I'm baffled.
> Could you please give me a "for-dumbs" definition of the problem ?
>
> Thanks,
> Giovanni
>
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