[seqfan] Re: A Fibonacci-related sequence -- suggestion

Neil Sloane njasloane at gmail.com
Fri Jun 8 16:34:10 CEST 2012


Certainly this should be in the OEIS!

On Thu, Jun 7, 2012 at 12:45 PM, Lars Blomberg <lars.blomberg at visit.se>wrote:

>
> Hello SeqFans,
>
> a(n) is the cycle length of the first differences of numbers k satisfying
>
> Fib(k) mod n = k mod n
>
>
>
> Example with n=3:
>
> Fib(k):
>
>
> 0,1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,10946,17711,28657,46368
>
> Fib(k) mod 3:
>
> 0,1,1,2,0,2,2,1,0,1,1,2,0,2,2,1,0,1,1,2,0,2,2,1,0
>
> k mod 3:
>
> 0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0
>
> accepted k values indicated by x:
>
> x,x,-,-,-,x,-,x,-,-,x,x,x,-,-,-,-,-,-,-,-,-,-,-,x
>
> accepted k values:
>
> 0,1,5,7,10,11,12,14,24
>
> first differences of k values:
>
> 1,4,2,3,1,1,2,10
>
> after this the cycle repeats, so a(3)=8.
>
>
>
> Beginning of the sequence:
>
> a(n)=3,8,3,8,6,16,3,8,14,10,4,28,24,16,3,36,6,18,11,16,15,48,3 for n=2..24
>
>
>
> It is not in OEIS, should it be?
>
>
>
> Regards,
>
> LBg
>
> _______________________________________________
>
> Seqfan Mailing list - http://list.seqfan.eu/
>



-- 
Dear Friends, I have now retired from AT&T. New coordinates:

Neil J. A. Sloane, President, OEIS Foundation
11 South Adelaide Avenue, Highland Park, NJ 08904, USA
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com



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