[seqfan] Re: Fibonacci sequences sharing no terms
franktaw at netscape.net
franktaw at netscape.net
Tue Sep 24 17:32:31 CEST 2013
Are you familiar with the Zeckendorf (or base Fibonacci) representation?
The numbers in Fib(4,6), expressed in that representation, are
(101,)1001, 10010, 100100, .... Obviously this pattern continues, and
obviously there can be no Fibonacci numbers in it.
Take a look at https://oeis.org/A035513 .
Franklin T. Adams-Watters
-----Original Message-----
From: Eric Angelini <Eric.Angelini at kntv.be>
To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
Sent: Tue, Sep 24, 2013 10:16 am
Subject: [seqfan] Fibonacci sequences sharing no terms
Hello Seqfans,
please forgive me if this question is naïve.
Consider Fib(1,2) =
1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,...
Now will Fib(4,6) = 4,6,10,16,26,42,68,110,178,288,466,... share at
some point
one term (or more) with Fib(1,2)?
If yes or no, do we know why? Are there constraints on 'a' and 'b'
leading to
a Fib(a,b) which will never share any term with Fib(1,2)?
Many thanks,
É.
[I've never subscribed to Fibonacci Quarterly...]
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