[seqfan] a(n) > cumulative sum of digits
Eric Angelini
Eric.Angelini at kntv.be
Wed Nov 12 00:14:20 CET 2014
Hello SeqFans,
Always extend T with the smallest a(n) such that a(n) > cumulative sum of T's digits so far:
T=10,11,12,13,20,21,22,30,31,32,40,41,50,60,61,70,80,90,100,101,102,103,104,105,110,111,120,...
If I'm not wrong, the table below shows [n,a(n),Q] with Q the cumulative sum so far:
1,10,1
2,11,3
3,12,6
4,13,10
5,20,12
6,21,15
7,22,19,
8,30,22
9,31,26
10,32,31
11,40,35
12,41,40
13,50,45
14,60,51
15,61,58,
16,70,65
17,80,73
18,90,82
19,100,83
20,101,85
21,102,88
22,103,92
23, 104,97
24,105,103
25,110,105
26,111,108
27,120,111,
...
Best,
É.
Catapulté de mon aPhone
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