[seqfan] Re: a(n) > cumulative sum of digits

[Bob Selcoe]

Hi Eric,

Just to clarify, you mean by "cumulative" that a(n) > cumulative sum  of T's 
digits so far, including a(n), yes?  Otherwise you'd get a very different 
(but equally interesting?) sequence.

Perhaps it would help to specify a(n) = sum {i=1..a(n)} i = digits of a(n).

Cheers,
Bob Selcoe

--------------------------------------------------
From: "Eric Angelini" <Eric.Angelini at kntv.be>
Sent: Tuesday, November 11, 2014 5:14 PM
To: "Sequence Discussion list" <seqfan at list.seqfan.eu>
Subject: [seqfan] a(n) > cumulative sum of digits

>
> Hello SeqFans,
> Always extend T with the smallest a(n) such that a(n) > cumulative sum  of 
> T's digits so far:
>
> T=10,11,12,13,20,21,22,30,31,32,40,41,50,60,61,70,80,90,100,101,102,103,104,105,110,111,120,...
>
> If I'm not wrong, the table below shows [n,a(n),Q] with Q the cumulative 
> sum so far:
>
> 1,10,1
> 2,11,3
> 3,12,6
> 4,13,10
> 5,20,12
> 6,21,15
> 7,22,19,
> 8,30,22
> 9,31,26
> 10,32,31
> 11,40,35
> 12,41,40
> 13,50,45
> 14,60,51
> 15,61,58,
> 16,70,65
> 17,80,73
> 18,90,82
> 19,100,83
> 20,101,85
> 21,102,88
> 22,103,92
> 23, 104,97
> 24,105,103
> 25,110,105
> 26,111,108
> 27,120,111,
> ...
>
> Best,
> É.
>
> Catapulté de mon aPhone
>
> _______________________________________________
>
> Seqfan Mailing list - http://list.seqfan.eu/
>