[seqfan] Re: A265182

[Reinhard Zumkeller]

I did correct the data ofA265183, confirm Lars' corrections of A265182,
and added b-files for both.

Best regards
Reinhard


2015-12-05 19:15 GMT+01:00 Neil Sloane <njasloane at gmail.com>:

> no, you are probably right, I calculated them by hand and asked someone to
> check them, saying they (meaning A265182 and A265183) were probably wrong.
> please go ahead and make those corrections and extend them.
>
>
>
> Best regards
> Neil
>
> Neil J. A. Sloane, President, OEIS Foundation.
> 11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
> Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
> Phone: 732 828 6098; home page: http://NeilSloane.com
> Email: njasloane at gmail.com
>
>
> On Sat, Dec 5, 2015 at 4:02 AM, Lars Blomberg <lars.blomberg at visit.se>
> wrote:
>
> >
> >
> > Hello,
> >
> >
> >
> > Attempting to reproduce A265182, I get a rather different result:
> >
> > OEIS: 1, 0, 0, 0, 0, 0, 0, 0, 0, 3, 3, 5, 3, 3, 3, 3, 3, 3, 3, 0, 5, 0,
> 0,
> > 1, 0, 0, 0, 0, 0, 0, 5, 0, 0, 0, 0, 0, 0, 0, 1, 0, 5
> >
> > Mine: 1, 0, 0, 0, 0, 0, 0, 0, 0, 3, 3, 5, 5, 5, 5, 5, 5, 5, 5, 0, 5, 0,
> 0,
> > 1, 1, 0, 0, 0, 0, 0, 5, 0, 0, 0, 0, 1, 0, 0, 1, 0, 5
> >
> >
> >
> > For n=12 the substrings are 1,2,12 and the products  1*1=1,  1*2=2,
> 2*1=2,
> > 1*12=12,             12*1=12.
> >
> > And similarly for n=13: substrings 1,3,13, products  1*1=1,  1*3=3,
> 3*1=3n
> > 1*13=13,             13*1=13.
> >
> > So I find a(13)=5, not 3.
> >
> >
> >
> > And for n=25: substrings 2,5,25, product 5*5=25.
> >
> > So I find a(25)=1, not 0.
> >
> > Similar situation for n=36.
> >
> >
> >
> > Am I missing something here?
> >
> >
> >
> > /Lars B
> >
> >
> > _______________________________________________
> >
> > Seqfan Mailing list - http://list.seqfan.eu/
> >
>
> _______________________________________________
>
> Seqfan Mailing list - http://list.seqfan.eu/
>