[seqfan] Re: A265182

[Neil Sloane]

no, you are probably right, I calculated them by hand and asked someone to
check them, saying they (meaning A265182 and A265183) were probably wrong.
please go ahead and make those corrections and extend them.



Best regards
Neil

Neil J. A. Sloane, President, OEIS Foundation.
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com


On Sat, Dec 5, 2015 at 4:02 AM, Lars Blomberg <lars.blomberg at visit.se>
wrote:

>
>
> Hello,
>
>
>
> Attempting to reproduce A265182, I get a rather different result:
>
> OEIS: 1, 0, 0, 0, 0, 0, 0, 0, 0, 3, 3, 5, 3, 3, 3, 3, 3, 3, 3, 0, 5, 0, 0,
> 1, 0, 0, 0, 0, 0, 0, 5, 0, 0, 0, 0, 0, 0, 0, 1, 0, 5
>
> Mine: 1, 0, 0, 0, 0, 0, 0, 0, 0, 3, 3, 5, 5, 5, 5, 5, 5, 5, 5, 0, 5, 0, 0,
> 1, 1, 0, 0, 0, 0, 0, 5, 0, 0, 0, 0, 1, 0, 0, 1, 0, 5
>
>
>
> For n=12 the substrings are 1,2,12 and the products  1*1=1,  1*2=2, 2*1=2,
> 1*12=12,             12*1=12.
>
> And similarly for n=13: substrings 1,3,13, products  1*1=1,  1*3=3,  3*1=3n
> 1*13=13,             13*1=13.
>
> So I find a(13)=5, not 3.
>
>
>
> And for n=25: substrings 2,5,25, product 5*5=25.
>
> So I find a(25)=1, not 0.
>
> Similar situation for n=36.
>
>
>
> Am I missing something here?
>
>
>
> /Lars B
>
>
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