[seqfan] Re: The a(n)th term of S ends with the a(n)th digit of S

Reinhard Zumkeller reinhard.zumkeller at gmail.com
Thu Jan 15 22:48:04 CET 2015


is 10 missing in S ?

2015-01-15 21:03 GMT+01:00 Eric Angelini <Eric.Angelini at kntv.be>:

> Hello SeqFans,
> start S with 1
> Extend S with a(n) such that a(n) is the smallest unused integer so far
> that ends with the a(n)th digit of S.
>
> (so, if the 49th digit of S is a 0, then the 49th integer of S must be the
> smallest unused integer so far that ends with 0)
>
> S =
> 1,2,3,4,5,6,7,8,9,11,21,12,31,41,22,13,51,14,61,32,42,71,23,15,81,91,24,16,101,33,52,34,62,17,...
>
> Table below:
> The digit ranks in S are (vertically) given by Dig/Dig -- digit #49 is
> here ----+
> S is S
>       |
> n is n
>       |
>
> Dig   1 2 3 4 5 6 7 8 9 11 11 11 11 11 22 22 22 22 22 33 33 3...
>       4
> Dig                     01 23 45 67 89 01 23 45 67 89 01 23 4...
>       9
> S =
> 1,2,3,4,5,6,7,8,9,11,21,12,31,41,22,13,51,14,61,32,42,71,23,15,81,91,24,16,101,33,52,34,62,17,...,10,
> n = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
> 27 28  29 30 31 32 33 34,... 49
>
> S is a permutation of the integers > 0.
>
> https://oeis.org/A126968 is not.
>
> Best,
> É.
>
>
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>
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>



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