[seqfan] Re: Question from Karol Penson

[Max Alekseyev]

A straightforward formula for the coefficient of x^n in [1-(1-x)^(1/m)]^p:

\sum_{i=0}^p \binom{p}{i} \binom{i/m}{n} (-1)^{i+n}

Regards,
Max


On Wed, Jun 3, 2015 at 4:18 PM, penson at lptl.jussieu.fr <
penson at lptl.jussieu.fr> wrote:

> Assume p=2,3,... and m=2,3.... .
> Does anyone know  a quick way to obtain the coefficient of x^n in the
> expansion of
>
>     [1-(1-x)^(1/m)]^p
>
>  as a function of p and m ?
>
>    Thanks,
>
> Karol Penson
>
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