[seqfan] Re: Question from Karol Penson

[Karol PENSON]

Max,

many thanks for your expeditious answer.  It works, I have checked it !

Best regards,

  Karol Penson


On 03/06/2015 17:20, Max Alekseyev wrote:
> A straightforward formula for the coefficient of x^n in [1-(1-x)^(1/m)]^p:
>
> \sum_{i=0}^p \binom{p}{i} \binom{i/m}{n} (-1)^{i+n}
>
> Regards,
> Max
>
>
> On Wed, Jun 3, 2015 at 4:18 PM, penson at lptl.jussieu.fr <
> penson at lptl.jussieu.fr> wrote:
>
>> Assume p=2,3,... and m=2,3.... .
>> Does anyone know  a quick way to obtain the coefficient of x^n in the
>> expansion of
>>
>>      [1-(1-x)^(1/m)]^p
>>
>>   as a function of p and m ?
>>
>>     Thanks,
>>
>> Karol Penson
>>
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