[seqfan] Re: A086953

[Kevin Ryde]

shevelev at bgu.ac.il (Vladimir Shevelev) writes:
>
> the formula: "COMMENTS   a(n+3)=A024495(n)/2"

Re your a(3*k+1) = 2*A024495(3*k), just comparing sample values it looks
like that might hold for all n, ie. A086953 without initial 1 = 2*A024495.

There might also be a vaguely similar binomials A111927 = A024493 - 1 if
you were keen.  A111927 already has a cross ref to A024495.