[seqfan] Re: 2(x - 1)^x = x^x

[юрий герасимов]

Dear SeqFans.
I incorrectly asked my question. Sorry. The right wave is as follows:
n = ? iff a(n) = 1 where a(n) = floor((n + 1)^(n + 1)/n^(n + 1)):
4, 3, 3, 3, 2, 2, 2, 2, 2, 2, ...
Or, version of sequences for OEIS:
Three-format (powers of 2, triangular numbers, even numbers) sequence:
b(n) = binomial((n + 1), floor((n + 1)^(n + 1)/(n + 1))) + binomial((n + 1), 1):
2, 4, 8, 15, 21, 28, 35, ...
c(n) = binomial((n + 1), floor((n + 1)^(n + 1)/(n + 1))) :
0, 1, 4, 10, 15, 21, 28, ...
Thanks. JSG