[seqfan] Re: linear recurrence multiples

[Ehren Metcalfe]

You've written: 4*A007482(n) = A007482(n+1) + A007482(n-1) + 2*A007482(n-2).

Regarding an analogue for A015518, it looks like the best match is
4*A015518(n) = A015518(n+1) + A015518(n-1) + 6*A015518(n-2).