[seqfan] Re: Look left and say

israel at math.ubc.ca israel at math.ubc.ca
Fri Nov 15 01:05:35 CET 2019


Should that not be S = 0, 10, 11, 20, 12, 22, 30, 13, 23, 33, 40, 14, 24, 
34, 44, 50, 15, 25, 35, 45, 55, 60, 16, 26, 36, 46, 56, 66, 70, 17, 27, 37, 
47, 57, 67, 77, 80, 18, 28, 38, 48, 58, 68, 78, 88, 90, 19, 29, 39, 49, 59, 
69, 79, 89, ...?

Thus after after 23 you can have 33 (three 3's) rather than 40 (four 0's).

Cheers,
Robert


On Nov 14 2019, Éric Angelini wrote:

> Hello SeqFans, S = 0, 10, 11, 20, 12, 22, 30, 13, 23, 40, 14, 24, 34, 44, 
> 50, 15, 25, 35, 45, 55, 60, 16, 26, 36, 46, 56, 66, 70, 17, 27, 37, 47, 
> 57, 67, 77, 80, 18, 28, 38, 48, 58, 68, 78, 88, 90, 19, 29, 39, 49, 59, 
> 69, 79, 89, 93,...
>
>Pick any term (except the first one) - for instance 93
>(at the end); this 93 says "On my left, there are
>9 digits "3", altogether. Which is correct: from 0 to 89
>(both markers included) there are exactly nine digits 3 in S.
>
>S is always extended with the smallest integer that
>"says the truth" about the past of S.
>S is started with a(1) = 0.
>
>Could someone compute more terms and submit S to the OEIS 
>if S is not already there - with another a(1), for instance - 
>and if S is of interest?
>
>The second part of this mail is here (with another seq proposal):
>https://bit.ly/2CKDqFk
>Best,
>É.
>
>--
>Seqfan Mailing list - http://list.seqfan.eu/
>
>



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