[seqfan] Re: A025586/2

[Hugo Pfoertner]

There are many sequences divisible by a constant common factor, but
typically only after discarding some initial terms. This also applies to
A025586. But if discarding initial terms is an option, then why not discard
two initial terms of A025586 and divide by 4? Or equivalently, A056959(n) /
4 ?

On Mon, Oct 14, 2019 at 8:08 AM Frank Adams-watters via SeqFan <
seqfan at list.seqfan.eu> wrote:

> Yes (IMO). The half sequence should be added.
>
> Franklin T. Adams-Watters
>
>
> -----Original Message-----
> From: P. Michael Hutchins <pmh232 at gmail.com>
> To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
> Sent: Sun, Oct 13, 2019 11:51 pm
> Subject: [seqfan] A025586/2
>
> Every item in  A025586 <https://oeis.org/A025586> is even.  So we can
> factor out the 2s.  My feeling is that such produces a "purer" sequence -
> one that's more likely to be matched from some other domain.
>
> Is that enough to make a new sequence?
>
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