[seqfan] Re: A025586/2

[Peter Munn]

Hugo makes a good point to look at A056959 alongside A025586. I would
suggest creating A056959/2 (and probably A056959/4 also) rather than
A025586/2, employing a principle that if there is a concise definition
that results in a sequence starting one or a few terms earlier (and no
such definition starting many terms earlier), the definition giving more
terms should be used.

Best Regards,

Peter

On Mon, October 14, 2019 8:41 am, Hugo Pfoertner wrote:
> There are many sequences divisible by a constant common factor, but
> typically only after discarding some initial terms. This also applies to
> A025586. But if discarding initial terms is an option, then why not
> discard
> two initial terms of A025586 and divide by 4? Or equivalently, A056959(n)
> /
> 4 ?
>
> On Mon, Oct 14, 2019 at 8:08 AM Frank Adams-watters via SeqFan <
> seqfan at list.seqfan.eu> wrote:
>
>> Yes (IMO). The half sequence should be added.
>>
>> Franklin T. Adams-Watters
>>
>>
>> -----Original Message-----
>> From: P. Michael Hutchins <pmh232 at gmail.com>
>> To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
>> Sent: Sun, Oct 13, 2019 11:51 pm
>> Subject: [seqfan] A025586/2
>>
>> Every item in  A025586 <https://oeis.org/A025586> is even.  So we can
>> factor out the 2s.  My feeling is that such produces a "purer" sequence
>> -
>> one that's more likely to be matched from some other domain.
>>
>> Is that enough to make a new sequence?
>>
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