[seqfan] Re: A sequence connected to the Pythagorean triples

[Ali Sada]

 Thank you, Tom.
 a(n) = ((c^4-a^4-b^4)/288)^1/2, where a, b, and c are the Pythagorean triples ordered by increasing c then b. 

Best,
Ali


    On Sunday, June 12, 2022 at 01:15:42 PM GMT+1, Tom Duff <eigenvectors at gmail.com> wrote:  
 
 On Sun, Jun 12, 2022 at 3:06 AM Ali Sada via SeqFan <seqfan at list.seqfan.eu>
wrote:

> a(n) = ((c^4-a^4-b^4)/288)^1/2, where a, b, and c are the Pythagorean
> triples ordered by increasing c.
>
You need to specify how to order triples with the same c, like (20, 15, 25)
and (24, 7, 25).

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