[seqfan] Re: A sequence connected to the Pythagorean triples
Tom Duff
eigenvectors at gmail.com
Tue Jun 14 14:51:36 CEST 2022
I see you need to say which of a and b is larger. It looks like you've
chosen b>a. If you'd picked b<a, the sequence would start 1, 4, 9, 10, 16,
14, 25. (Sorry to chip away at difficulties a bit at a time, but I missed
this one on first reading.)
On Tue, Jun 14, 2022 at 3:29 AM Ali Sada via SeqFan <seqfan at list.seqfan.eu>
wrote:
> Thank you, Tom.
> a(n) = ((c^4-a^4-b^4)/288)^1/2, where a, b, and c are the Pythagorean
> triples ordered by increasing c then b.
>
> Best,
> Ali
>
>
> On Sunday, June 12, 2022 at 01:15:42 PM GMT+1, Tom Duff <
> eigenvectors at gmail.com> wrote:
>
> On Sun, Jun 12, 2022 at 3:06 AM Ali Sada via SeqFan <
> seqfan at list.seqfan.eu>
> wrote:
>
> > a(n) = ((c^4-a^4-b^4)/288)^1/2, where a, b, and c are the Pythagorean
> > triples ordered by increasing c.
> >
> You need to specify how to order triples with the same c, like (20, 15, 25)
> and (24, 7, 25).
>
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>
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