[math-fun] Sum of last ten digits

[Alexandre Wajnberg]

OK, I did'nt understood you made same seqs with other beginnings than
ours...
So I agree, there are a lot of loops around there... :-)


Thanx

Alexandre


De : Graeme McRae <g_m at mcraefamily.com>
Date : Thu, 8 Dec 2005 10:28:11 -0800
À : Alexandre Wajnberg <alexandre.wajnberg at skynet.be>
Objet : Re: [math-fun] Sum of last ten digits

Just taking the first one, if the sequence begins 0, 6, 1, 8, 7, 8, 6, 6, 3,
0, then the sequence through the repetition (loop length 8) is 0, 6, 1, 8,
7, 8, 6, 6, 3, 0, 45, 48, 51, 42, 36, 42, 39, 39, 45, 48, 51, 51, 45, 42,
39, 39, 45, 48, 51, 51, 45.
--Graeme
>  
> ----- Original Message -----
> 
> 
> De : Graeme  McRae <g_m at mcraefamily.com>
> Date : Thu, 8 Dec 2005 07:47:23  -0800
> 
> Searching randomly, I found that:
> A loop of  length 8 is possible, starting at 0, 6, 1, 8, 7, 8, 6, 6, 3, 0.
> A loop of  length 24 is possible, starting at 0, 4, 2, 1, 9, 7, 1, 7, 7, 4.
> A loop of  length 26 is possible, starting at 2, 3, 2, 7, 0, 9, 8, 7, 8, 4.
> A loop of  length 78 is possible, starting at 2, 2, 5, 2, 6, 0, 3, 8, 5,  7.
> --Graeme
>  
>> 
>> The nine sequences (beginning with  ...0 1; ...2; 9) involve digits in their
>> construction and our loops are made  of terms (numbers).
>> 
>> I tried your digit-propositions without success,  no "digit loops" hidden
>> inside.
>> I did this way: 
>> -pasting the nine  complete sequences (the beginning + the first loop + the
>> ten first terms of  the second loop) on a new page of my "word" program;
>> -compacting them  (removing all the "blanks" and the ",")
>> -compacting the same way your ten  digits propositions;
>> -searching, using the "find" function of my "word"  program.
>> I found only my control.
>> So I don't understand. May be I miss  a point?
>> Are you shure of your finding? Or of your sequences?
>> I send  you separately our complete sequences.
>> Thank you for your  interest.
>> 
>> Alexandre
>>  


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