Permutation Its Own Inverse?

[Leroy Quet]

[By the way, I am sending to old email address. Does new seq.fan address 
work yet?]

Form the triangle where a(n,m) is the (ceiling(n/m))th integer from among 
those positive integers not occurring earlier in the (concatenated) 
sequence.

So we have the triangle beginning:

1
3,2
6,5,4
10,8,9,7
15,13,12,14,11
21,18,17,19,20,16
28,25,24,23,26,27,22

Now, this may be an easily answered question, but, is this sequence (the 
triangle read by rows: 1,3,2,6,5,4,10,8,9,7,...) its own inverse 
permutation of the positive integers?

thanks,
Leroy Quet